4x^2-208x+929=0

Solution for 4x^2-208x+929=0 equation:

4x^2-208x+929=0

a = 4; b = -208; c = +929;
Δ = b2-4ac
Δ = -2082-4·4·929
Δ = 28400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28400}=\sqrt{400*71}=\sqrt{400}*\sqrt{71}=20\sqrt{71}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-208)-20\sqrt{71}}{2*4}=\frac{208-20\sqrt{71}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-208)+20\sqrt{71}}{2*4}=\frac{208+20\sqrt{71}}{8}
$